3x+10=7/2+.01x

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Solution for 3x+10=7/2+.01x equation: 



3x+10=7/2+.01x

We move all terms to the left:

3x+10-(7/2+.01x)=0



Domain of the equation: 2+.01x)!=0

We move all terms containing x to the left, all other terms to the right

.01x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

3x-(+.01x+7/2)+10=0

We get rid of parentheses

3x-.01x+10-7/2=0

We multiply all the terms by the denominator


3x*2-(.01x)*2-7+10*2=0

We add all the numbers together, and all the variables

3x*2-(+.01x)*2-7+10*2=0

We add all the numbers together, and all the variables

3x*2-(+.01x)*2+13=0

We multiply parentheses

3x*2-2x+13=0

Wy multiply elements

6x-2x+13=0

We add all the numbers together, and all the variables

4x+13=0

We move all terms containing x to the left, all other terms to the right

4x=-13

x=-13/4

x=-3+1/4

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