3x+10=4(x-3)-(x-2)

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Solution for 3x+10=4(x-3)-(x-2) equation:


Simplifying
3x + 10 = 4(x + -3) + -1(x + -2)

Reorder the terms:
10 + 3x = 4(x + -3) + -1(x + -2)

Reorder the terms:
10 + 3x = 4(-3 + x) + -1(x + -2)
10 + 3x = (-3 * 4 + x * 4) + -1(x + -2)
10 + 3x = (-12 + 4x) + -1(x + -2)

Reorder the terms:
10 + 3x = -12 + 4x + -1(-2 + x)
10 + 3x = -12 + 4x + (-2 * -1 + x * -1)
10 + 3x = -12 + 4x + (2 + -1x)

Reorder the terms:
10 + 3x = -12 + 2 + 4x + -1x

Combine like terms: -12 + 2 = -10
10 + 3x = -10 + 4x + -1x

Combine like terms: 4x + -1x = 3x
10 + 3x = -10 + 3x

Add '-3x' to each side of the equation.
10 + 3x + -3x = -10 + 3x + -3x

Combine like terms: 3x + -3x = 0
10 + 0 = -10 + 3x + -3x
10 = -10 + 3x + -3x

Combine like terms: 3x + -3x = 0
10 = -10 + 0
10 = -10

Solving
10 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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