3x+10=2(100-8x)

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Solution for 3x+10=2(100-8x) equation: 



3x+10=2(100-8x)

We move all terms to the left:

3x+10-(2(100-8x))=0

We add all the numbers together, and all the variables

3x-(2(-8x+100))+10=0



We calculate terms in parentheses: -(2(-8x+100)), so:

2(-8x+100)

We multiply parentheses

-16x+200

Back to the equation:

-(-16x+200)



We get rid of parentheses

3x+16x-200+10=0

We add all the numbers together, and all the variables

19x-190=0

We move all terms containing x to the left, all other terms to the right

19x=190

x=190/19

x=10

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