3x+10-2(x+2)=6+5(3-x)+3x

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Solution for 3x+10-2(x+2)=6+5(3-x)+3x equation: 



3x+10-2(x+2)=6+5(3-x)+3x

We move all terms to the left:

3x+10-2(x+2)-(6+5(3-x)+3x)=0

We add all the numbers together, and all the variables

3x-2(x+2)-(6+5(-1x+3)+3x)+10=0

We multiply parentheses

3x-2x-(6+5(-1x+3)+3x)-4+10=0



We calculate terms in parentheses: -(6+5(-1x+3)+3x), so:

6+5(-1x+3)+3x

determiningTheFunctionDomain
5(-1x+3)+3x+6

We add all the numbers together, and all the variables

3x+5(-1x+3)+6

We multiply parentheses

3x-5x+15+6

We add all the numbers together, and all the variables

-2x+21

Back to the equation:

-(-2x+21)



We add all the numbers together, and all the variables

x-(-2x+21)+6=0

We get rid of parentheses

x+2x-21+6=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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