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3x+1/3(6x-9)=1/2(10x-6)
We move all terms to the left:
3x+1/3(6x-9)-(1/2(10x-6))=0
Domain of the equation: 3(6x-9)!=0
x∈R
Domain of the equation: 2(10x-6))!=0We calculate fractions
x∈R
3x+(2x1/(3(6x-9)*2(10x-6)))+(-3x6/(3(6x-9)*2(10x-6)))=0
We calculate terms in parentheses: +(2x1/(3(6x-9)*2(10x-6))), so:
2x1/(3(6x-9)*2(10x-6))
We multiply all the terms by the denominator
2x1
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-3x6/(3(6x-9)*2(10x-6))), so:
-3x6/(3(6x-9)*2(10x-6))
We multiply all the terms by the denominator
-3x6
We add all the numbers together, and all the variables
-3x^6
We do not support expression: x^6
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