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3x+-9=(10+x)
We move all terms to the left:
3x+-9-((10+x))=0
We add all the numbers together, and all the variables
3x-((x+10))-9+=0
We add all the numbers together, and all the variables
3x-((x+10))=0
We calculate terms in parentheses: -((x+10)), so:We get rid of parentheses
(x+10)
We get rid of parentheses
x+10
Back to the equation:
-(x+10)
3x-x-10=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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