3x+-8=3(x+-4)+1

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Solution for 3x+-8=3(x+-4)+1 equation: 



3x+-8=3(x+-4)+1

We move all terms to the left:

3x+-8-(3(x+-4)+1)=0

We add all the numbers together, and all the variables

3x-(3(x-4)+1)-8+=0

We add all the numbers together, and all the variables

3x-(3(x-4)+1)=0



We calculate terms in parentheses: -(3(x-4)+1), so:

3(x-4)+1

We multiply parentheses

3x-12+1

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)



We get rid of parentheses

3x-3x+11=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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