3x+-7=11x+(8x+-2)

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Solution for 3x+-7=11x+(8x+-2) equation: 



3x+-7=11x+(8x+-2)

We move all terms to the left:

3x+-7-(11x+(8x+-2))=0

We add all the numbers together, and all the variables

3x-(11x+(8x-2))-7+=0

We add all the numbers together, and all the variables

3x-(11x+(8x-2))=0



We calculate terms in parentheses: -(11x+(8x-2)), so:

11x+(8x-2)

We get rid of parentheses

11x+8x-2

We add all the numbers together, and all the variables

19x-2

Back to the equation:

-(19x-2)



We get rid of parentheses

3x-19x+2=0

We add all the numbers together, and all the variables

-16x+2=0

We move all terms containing x to the left, all other terms to the right

-16x=-2

x=-2/-16

x=1/8

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