3x+-4(x-3)=10

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Solution for 3x+-4(x-3)=10 equation: 



3x+-4(x-3)=10

We move all terms to the left:

3x+-4(x-3)-(10)=0

determiningTheFunctionDomain
3x-4(x-3)-10+=0

We add all the numbers together, and all the variables

3x-4(x-3)=0

We multiply parentheses

3x-4x+12=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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