3x+(x+1)=69

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Solution for 3x+(x+1)=69 equation: 



3x+(x+1)=69

We move all terms to the left:

3x+(x+1)-(69)=0

We get rid of parentheses

3x+x+1-69=0

We add all the numbers together, and all the variables

4x-68=0

We move all terms containing x to the left, all other terms to the right

4x=68

x=68/4

x=17

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