3x+(X*x)/16x+4x=99

Solution for 3x+(X*x)/16x+4x=99 equation:

3x+(x*x)/16x+4x=99

We move all terms to the left:

3x+(x*x)/16x+4x-(99)=0


Domain of the equation: 16x!=0

x!=0/16

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(+x*x)/16x+4x-99=0

We add all the numbers together, and all the variables

7x+(+x*x)/16x-99=0

We multiply all the terms by the denominator


7x*16x+(+x*x)-99*16x=0

Wy multiply elements

112x^2+(+x*x)-1584x=0

We get rid of parentheses

112x^2+x*x-1584x=0

We add all the numbers together, and all the variables

112x^2-1584x+x*x=0

Wy multiply elements

112x^2+x^2-1584x=0

We add all the numbers together, and all the variables

113x^2-1584x=0

a = 113; b = -1584; c = 0;
Δ = b2-4ac
Δ = -15842-4·113·0
Δ = 2509056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2509056}=1584$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1584)-1584}{2*113}=\frac{0}{226}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1584)+1584}{2*113}=\frac{3168}{226}
=14+2/113
$