3x+(4x-5)=12

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Solution for 3x+(4x-5)=12 equation: 



3x+(4x-5)=12

We move all terms to the left:

3x+(4x-5)-(12)=0

We get rid of parentheses

3x+4x-5-12=0

We add all the numbers together, and all the variables

7x-17=0

We move all terms containing x to the left, all other terms to the right

7x=17

x=17/7

x=2+3/7

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