3x+(4x+19)=180

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Solution for 3x+(4x+19)=180 equation: 



3x+(4x+19)=180

We move all terms to the left:

3x+(4x+19)-(180)=0

We get rid of parentheses

3x+4x+19-180=0

We add all the numbers together, and all the variables

7x-161=0

We move all terms containing x to the left, all other terms to the right

7x=161

x=161/7

x=23

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