3x+(4-x)/5=x-1

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Solution for 3x+(4-x)/5=x-1 equation: 



3x+(4-x)/5=x-1

We move all terms to the left:

3x+(4-x)/5-(x-1)=0

We add all the numbers together, and all the variables

3x+(-1x+4)/5-(x-1)=0

We get rid of parentheses

3x+(-1x+4)/5-x+1=0

We multiply all the terms by the denominator


3x*5+(-1x+4)-x*5+1*5=0

We add all the numbers together, and all the variables

3x*5+(-1x+4)-x*5+5=0

Wy multiply elements

15x+(-1x+4)-5x+5=0

We get rid of parentheses

15x-1x-5x+4+5=0

We add all the numbers together, and all the variables

9x+9=0

We move all terms containing x to the left, all other terms to the right

9x=-9

x=-9/9

x=-1

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