3x+(3x-5)+(4x+2)=62

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Solution for 3x+(3x-5)+(4x+2)=62 equation:


Simplifying
3x + (3x + -5) + (4x + 2) = 62

Reorder the terms:
3x + (-5 + 3x) + (4x + 2) = 62

Remove parenthesis around (-5 + 3x)
3x + -5 + 3x + (4x + 2) = 62

Reorder the terms:
3x + -5 + 3x + (2 + 4x) = 62

Remove parenthesis around (2 + 4x)
3x + -5 + 3x + 2 + 4x = 62

Reorder the terms:
-5 + 2 + 3x + 3x + 4x = 62

Combine like terms: -5 + 2 = -3
-3 + 3x + 3x + 4x = 62

Combine like terms: 3x + 3x = 6x
-3 + 6x + 4x = 62

Combine like terms: 6x + 4x = 10x
-3 + 10x = 62

Solving
-3 + 10x = 62

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 10x = 62 + 3

Combine like terms: -3 + 3 = 0
0 + 10x = 62 + 3
10x = 62 + 3

Combine like terms: 62 + 3 = 65
10x = 65

Divide each side by '10'.
x = 6.5

Simplifying
x = 6.5

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