3x+(2y+z)=(3x+2y)+z

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Solution for 3x+(2y+z)=(3x+2y)+z equation:


Simplifying
3x + (2y + z) = (3x + 2y) + z

Remove parenthesis around (2y + z)
3x + 2y + z = (3x + 2y) + z

Remove parenthesis around (3x + 2y)
3x + 2y + z = 3x + 2y + z

Add '-3x' to each side of the equation.
3x + 2y + -3x + z = 3x + 2y + -3x + z

Reorder the terms:
3x + -3x + 2y + z = 3x + 2y + -3x + z

Combine like terms: 3x + -3x = 0
0 + 2y + z = 3x + 2y + -3x + z
2y + z = 3x + 2y + -3x + z

Reorder the terms:
2y + z = 3x + -3x + 2y + z

Combine like terms: 3x + -3x = 0
2y + z = 0 + 2y + z
2y + z = 2y + z

Add '-2y' to each side of the equation.
2y + -2y + z = 2y + -2y + z

Combine like terms: 2y + -2y = 0
0 + z = 2y + -2y + z
z = 2y + -2y + z

Combine like terms: 2y + -2y = 0
z = 0 + z
z = z

Add '-1z' to each side of the equation.
z + -1z = z + -1z

Combine like terms: z + -1z = 0
0 = z + -1z

Combine like terms: z + -1z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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