3x+(2x+5)+(3x-10)+(2x+15)=360

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Solution for 3x+(2x+5)+(3x-10)+(2x+15)=360 equation: 



3x+(2x+5)+(3x-10)+(2x+15)=360

We move all terms to the left:

3x+(2x+5)+(3x-10)+(2x+15)-(360)=0

We get rid of parentheses

3x+2x+3x+2x+5-10+15-360=0

We add all the numbers together, and all the variables

10x-350=0

We move all terms containing x to the left, all other terms to the right

10x=350

x=350/10

x=35

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