3x+(10(12/5)x)=-2

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Solution for 3x+(10(12/5)x)=-2 equation: 



3x+(10(12/5)x)=-2

We move all terms to the left:

3x+(10(12/5)x)-(-2)=0



Domain of the equation: 5)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x+(10(+12/5)x)-(-2)=0

We add all the numbers together, and all the variables

3x+(10(+12/5)x)+2=0

We multiply all the terms by the denominator


3x*5)x)+(10(+2*5)x)+12=0

We add all the numbers together, and all the variables

3x*5)x)+(1010x)+12=0

We add all the numbers together, and all the variables

3x*5)x)+1010x+12=0

Wy multiply elements

15x^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$

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