3x+(1/2)=(1/4)x+6

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Solution for 3x+(1/2)=(1/4)x+6 equation: 



3x+(1/2)=(1/4)x+6

We move all terms to the left:

3x+(1/2)-((1/4)x+6)=0



Domain of the equation: 4)x+6)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x-((+1/4)x+6)+(+1/2)=0

We get rid of parentheses

3x-((+1/4)x+6)+1/2=0

We calculate fractions


3x+()/4x+6)*2)+4x/4x+6)*2)=0

We calculate fractions


3x+(()*4x)/16x^2+6*2)+4x*4x)/16x^2=0

We multiply all the terms by the denominator


3x*16x^2+(()*4x)+6*2)+4x*4x)=0



We calculate terms in parentheses: +(()*4x), so:

()*4x



Wy multiply elements

48x^3+48x^2+(()*4x)=0



We calculate terms in parentheses: +(()*4x), so:

()*4x



We do not support expression: x^3

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