3x*x-19x-50=0

Solution for 3x*x-19x-50=0 equation:

3x*x-19x-50=0

We add all the numbers together, and all the variables

-19x+3x*x-50=0

Wy multiply elements

3x^2-19x-50=0

a = 3; b = -19; c = -50;
Δ = b2-4ac
Δ = -192-4·3·(-50)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-31}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+31}{2*3}=\frac{50}{6}
=8+1/3
$