3x*4x=24200

Solution for 3x*4x=24200 equation:

3x*4x=24200

We move all terms to the left:

3x*4x-(24200)=0

Wy multiply elements

12x^2-24200=0

a = 12; b = 0; c = -24200;
Δ = b2-4ac
Δ = 02-4·12·(-24200)
Δ = 1161600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1161600}=\sqrt{193600*6}=\sqrt{193600}*\sqrt{6}=440\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-440\sqrt{6}}{2*12}=\frac{0-440\sqrt{6}}{24}
=-\frac{440\sqrt{6}}{24}
=-\frac{55\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+440\sqrt{6}}{2*12}=\frac{0+440\sqrt{6}}{24}
=\frac{440\sqrt{6}}{24}
=\frac{55\sqrt{6}}{3}
$