3x*4x+40=360

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Solution for 3x*4x+40=360 equation:



3x*4x+40=360
We move all terms to the left:
3x*4x+40-(360)=0
We add all the numbers together, and all the variables
3x*4x-320=0
Wy multiply elements
12x^2-320=0
a = 12; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·12·(-320)
Δ = 15360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{15360}=\sqrt{1024*15}=\sqrt{1024}*\sqrt{15}=32\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{15}}{2*12}=\frac{0-32\sqrt{15}}{24} =-\frac{32\sqrt{15}}{24} =-\frac{4\sqrt{15}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{15}}{2*12}=\frac{0+32\sqrt{15}}{24} =\frac{32\sqrt{15}}{24} =\frac{4\sqrt{15}}{3} $

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