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3x*23/x=16x+3
We move all terms to the left:
3x*23/x-(16x+3)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
3x*23/x-16x-3=0
We multiply all the terms by the denominator
3x*23-16x*x-3*x=0
We add all the numbers together, and all the variables
-3x+3x*23-16x*x=0
Wy multiply elements
-16x^2-3x+69x=0
We add all the numbers together, and all the variables
-16x^2+66x=0
a = -16; b = 66; c = 0;
Δ = b2-4ac
Δ = 662-4·(-16)·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-66}{2*-16}=\frac{-132}{-32} =4+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+66}{2*-16}=\frac{0}{-32} =0 $
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