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3x(x-1)=468
We move all terms to the left:
3x(x-1)-(468)=0
We multiply parentheses
3x^2-3x-468=0
a = 3; b = -3; c = -468;
Δ = b2-4ac
Δ = -32-4·3·(-468)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-75}{2*3}=\frac{-72}{6} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+75}{2*3}=\frac{78}{6} =13 $
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