3x(x-5)=17

Solution for 3x(x-5)=17 equation:

3x(x-5)=17

We move all terms to the left:

3x(x-5)-(17)=0

We multiply parentheses

3x^2-15x-17=0

a = 3; b = -15; c = -17;
Δ = b2-4ac
Δ = -152-4·3·(-17)
Δ = 429
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{429}}{2*3}=\frac{15-\sqrt{429}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{429}}{2*3}=\frac{15+\sqrt{429}}{6}
$