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3x(x-4)=12x
We move all terms to the left:
3x(x-4)-(12x)=0
We add all the numbers together, and all the variables
-12x+3x(x-4)=0
We multiply parentheses
3x^2-12x-12x=0
We add all the numbers together, and all the variables
3x^2-24x=0
a = 3; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·3·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*3}=\frac{48}{6} =8 $
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