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3x(x-3)-4x+12=0
We add all the numbers together, and all the variables
-4x+3x(x-3)+12=0
We multiply parentheses
3x^2-4x-9x+12=0
We add all the numbers together, and all the variables
3x^2-13x+12=0
a = 3; b = -13; c = +12;
Δ = b2-4ac
Δ = -132-4·3·12
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*3}=\frac{8}{6} =1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*3}=\frac{18}{6} =3 $
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