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3x(x-2)=x-5
We move all terms to the left:
3x(x-2)-(x-5)=0
We multiply parentheses
3x^2-6x-(x-5)=0
We get rid of parentheses
3x^2-6x-x+5=0
We add all the numbers together, and all the variables
3x^2-7x+5=0
a = 3; b = -7; c = +5;
Δ = b2-4ac
Δ = -72-4·3·5
Δ = -11
Delta is less than zero, so there is no solution for the equation
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