3x(x-1)-2(x+3)(x+5)=x2-2x+1

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Solution for 3x(x-1)-2(x+3)(x+5)=x2-2x+1 equation: 



3x(x-1)-2(x+3)(x+5)=x2-2x+1

We move all terms to the left:

3x(x-1)-2(x+3)(x+5)-(x2-2x+1)=0

We add all the numbers together, and all the variables

-(+x^2-2x+1)+3x(x-1)-2(x+3)(x+5)=0

We multiply parentheses

-(+x^2-2x+1)+3x^2-3x-2(x+3)(x+5)=0

We get rid of parentheses

-x^2+3x^2+2x-3x-2(x+3)(x+5)-1=0

We multiply parentheses ..

-x^2+3x^2-2(+x^2+5x+3x+15)+2x-3x-1=0

We add all the numbers together, and all the variables

2x^2-2(+x^2+5x+3x+15)-1x-1=0

We multiply parentheses

2x^2-2x^2-10x-6x-1x-30-1=0

We add all the numbers together, and all the variables

-17x-31=0

We move all terms containing x to the left, all other terms to the right

-17x=31

x=31/-17

x=-1+14/17

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