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3x(x+7)+5x(x-2)=11x+60.5
We move all terms to the left:
3x(x+7)+5x(x-2)-(11x+60.5)=0
We multiply parentheses
3x^2+5x^2+21x-10x-(11x+60.5)=0
We get rid of parentheses
3x^2+5x^2+21x-10x-11x-60.5=0
We add all the numbers together, and all the variables
8x^2-60.5=0
a = 8; b = 0; c = -60.5;
Δ = b2-4ac
Δ = 02-4·8·(-60.5)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*8}=\frac{-44}{16} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*8}=\frac{44}{16} =2+3/4 $
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