3x(x+6)=366

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Solution for 3x(x+6)=366 equation:



3x(x+6)=366
We move all terms to the left:
3x(x+6)-(366)=0
We multiply parentheses
3x^2+18x-366=0
a = 3; b = 18; c = -366;
Δ = b2-4ac
Δ = 182-4·3·(-366)
Δ = 4716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4716}=\sqrt{36*131}=\sqrt{36}*\sqrt{131}=6\sqrt{131}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{131}}{2*3}=\frac{-18-6\sqrt{131}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{131}}{2*3}=\frac{-18+6\sqrt{131}}{6} $

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