3x(x+2)=90

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Solution for 3x(x+2)=90 equation:



3x(x+2)=90
We move all terms to the left:
3x(x+2)-(90)=0
We multiply parentheses
3x^2+6x-90=0
a = 3; b = 6; c = -90;
Δ = b2-4ac
Δ = 62-4·3·(-90)
Δ = 1116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1116}=\sqrt{36*31}=\sqrt{36}*\sqrt{31}=6\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{31}}{2*3}=\frac{-6-6\sqrt{31}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{31}}{2*3}=\frac{-6+6\sqrt{31}}{6} $

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