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3x(x+14)=90
We move all terms to the left:
3x(x+14)-(90)=0
We multiply parentheses
3x^2+42x-90=0
a = 3; b = 42; c = -90;
Δ = b2-4ac
Δ = 422-4·3·(-90)
Δ = 2844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2844}=\sqrt{36*79}=\sqrt{36}*\sqrt{79}=6\sqrt{79}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6\sqrt{79}}{2*3}=\frac{-42-6\sqrt{79}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6\sqrt{79}}{2*3}=\frac{-42+6\sqrt{79}}{6} $
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