3x(x+10)=600

Solution for 3x(x+10)=600 equation:

3x(x+10)=600

We move all terms to the left:

3x(x+10)-(600)=0

We multiply parentheses

3x^2+30x-600=0

a = 3; b = 30; c = -600;
Δ = b2-4ac
Δ = 302-4·3·(-600)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-90}{2*3}=\frac{-120}{6}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+90}{2*3}=\frac{60}{6}
=10
$