3x(8x+9)=0

Solution for 3x(8x+9)=0 equation:

3x(8x+9)=0

We multiply parentheses

24x^2+27x=0

a = 24; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·24·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*24}=\frac{-54}{48}
=-1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*24}=\frac{0}{48}
=0
$