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3x(6x+2)-7x=396x
We move all terms to the left:
3x(6x+2)-7x-(396x)=0
We add all the numbers together, and all the variables
-403x+3x(6x+2)=0
We multiply parentheses
18x^2-403x+6x=0
We add all the numbers together, and all the variables
18x^2-397x=0
a = 18; b = -397; c = 0;
Δ = b2-4ac
Δ = -3972-4·18·0
Δ = 157609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{157609}=397$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-397)-397}{2*18}=\frac{0}{36} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-397)+397}{2*18}=\frac{794}{36} =22+1/18 $
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