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3x(6+2x)=4x
We move all terms to the left:
3x(6+2x)-(4x)=0
We add all the numbers together, and all the variables
3x(2x+6)-4x=0
We add all the numbers together, and all the variables
-4x+3x(2x+6)=0
We multiply parentheses
6x^2-4x+18x=0
We add all the numbers together, and all the variables
6x^2+14x=0
a = 6; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·6·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*6}=\frac{-28}{12} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*6}=\frac{0}{12} =0 $
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