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3x(3x-14)=-49
We move all terms to the left:
3x(3x-14)-(-49)=0
We add all the numbers together, and all the variables
3x(3x-14)+49=0
We multiply parentheses
9x^2-42x+49=0
a = 9; b = -42; c = +49;
Δ = b2-4ac
Δ = -422-4·9·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{42}{18}=2+1/3$
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