3x(3/2)-24=0

Solution for 3x(3/2)-24=0 equation:

3x(3/2)-24=0

We add all the numbers together, and all the variables

3x(+3/2)-24=0

We multiply parentheses

9x^2-24=0

a = 9; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·9·(-24)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*9}=\frac{0-12\sqrt{6}}{18}
=-\frac{12\sqrt{6}}{18}
=-\frac{2\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*9}=\frac{0+12\sqrt{6}}{18}
=\frac{12\sqrt{6}}{18}
=\frac{2\sqrt{6}}{3}
$