3x(2x-4)=28-2x

Solution for 3x(2x-4)=28-2x equation:

3x(2x-4)=28-2x

We move all terms to the left:

3x(2x-4)-(28-2x)=0

We add all the numbers together, and all the variables

3x(2x-4)-(-2x+28)=0

We multiply parentheses

6x^2-12x-(-2x+28)=0

We get rid of parentheses

6x^2-12x+2x-28=0

We add all the numbers together, and all the variables

6x^2-10x-28=0

a = 6; b = -10; c = -28;
Δ = b2-4ac
Δ = -102-4·6·(-28)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{193}}{2*6}=\frac{10-2\sqrt{193}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{193}}{2*6}=\frac{10+2\sqrt{193}}{12}
$