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3x(2x-34)=0
We multiply parentheses
6x^2-102x=0
a = 6; b = -102; c = 0;
Δ = b2-4ac
Δ = -1022-4·6·0
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10404}=102$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-102}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+102}{2*6}=\frac{204}{12} =17 $
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