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3x(2x-3)=104
We move all terms to the left:
3x(2x-3)-(104)=0
We multiply parentheses
6x^2-9x-104=0
a = 6; b = -9; c = -104;
Δ = b2-4ac
Δ = -92-4·6·(-104)
Δ = 2577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{2577}}{2*6}=\frac{9-\sqrt{2577}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{2577}}{2*6}=\frac{9+\sqrt{2577}}{12} $
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