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3x(2x+7)=180
We move all terms to the left:
3x(2x+7)-(180)=0
We multiply parentheses
6x^2+21x-180=0
a = 6; b = 21; c = -180;
Δ = b2-4ac
Δ = 212-4·6·(-180)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-69}{2*6}=\frac{-90}{12} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+69}{2*6}=\frac{48}{12} =4 $
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