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3x(2x+5)=(6x+1)(x+3)
We move all terms to the left:
3x(2x+5)-((6x+1)(x+3))=0
We multiply parentheses
6x^2+15x-((6x+1)(x+3))=0
We multiply parentheses ..
6x^2-((+6x^2+18x+x+3))+15x=0
We calculate terms in parentheses: -((+6x^2+18x+x+3)), so:We add all the numbers together, and all the variables
(+6x^2+18x+x+3)
We get rid of parentheses
6x^2+18x+x+3
We add all the numbers together, and all the variables
6x^2+19x+3
Back to the equation:
-(6x^2+19x+3)
6x^2+15x-(6x^2+19x+3)=0
We get rid of parentheses
6x^2-6x^2+15x-19x-3=0
We add all the numbers together, and all the variables
-4x-3=0
We move all terms containing x to the left, all other terms to the right
-4x=3
x=3/-4
x=-3/4
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