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3x(2x+20)=2.8
We move all terms to the left:
3x(2x+20)-(2.8)=0
We add all the numbers together, and all the variables
3x(2x+20)-2.8=0
We multiply parentheses
6x^2+60x-2.8=0
a = 6; b = 60; c = -2.8;
Δ = b2-4ac
Δ = 602-4·6·(-2.8)
Δ = 3667.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-\sqrt{3667.2}}{2*6}=\frac{-60-\sqrt{3667.2}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+\sqrt{3667.2}}{2*6}=\frac{-60+\sqrt{3667.2}}{12} $
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