3x(2x+2)=8x-3-2x+3

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Solution for 3x(2x+2)=8x-3-2x+3 equation: 



3x(2x+2)=8x-3-2x+3

We move all terms to the left:

3x(2x+2)-(8x-3-2x+3)=0

We add all the numbers together, and all the variables

3x(2x+2)-(+6x)=0

We multiply parentheses

6x^2+6x-(+6x)=0

We get rid of parentheses

6x^2+6x-6x=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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