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3x(2x+1)=6x(x-1)+2x-17
We move all terms to the left:
3x(2x+1)-(6x(x-1)+2x-17)=0
We multiply parentheses
6x^2+3x-(6x(x-1)+2x-17)=0
We calculate terms in parentheses: -(6x(x-1)+2x-17), so:We get rid of parentheses
6x(x-1)+2x-17
We add all the numbers together, and all the variables
2x+6x(x-1)-17
We multiply parentheses
6x^2+2x-6x-17
We add all the numbers together, and all the variables
6x^2-4x-17
Back to the equation:
-(6x^2-4x-17)
6x^2-6x^2+3x+4x+17=0
We add all the numbers together, and all the variables
7x+17=0
We move all terms containing x to the left, all other terms to the right
7x=-17
x=-17/7
x=-2+3/7
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