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3x(2-x)=10
We move all terms to the left:
3x(2-x)-(10)=0
We add all the numbers together, and all the variables
3x(-1x+2)-10=0
We multiply parentheses
-3x^2+6x-10=0
a = -3; b = 6; c = -10;
Δ = b2-4ac
Δ = 62-4·(-3)·(-10)
Δ = -84
Delta is less than zero, so there is no solution for the equation
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