3x(-6-2x)=-10

Solution for 3x(-6-2x)=-10 equation:

3x(-6-2x)=-10

We move all terms to the left:

3x(-6-2x)-(-10)=0

We add all the numbers together, and all the variables

3x(-2x-6)-(-10)=0

We add all the numbers together, and all the variables

3x(-2x-6)+10=0

We multiply parentheses

-6x^2-18x+10=0

a = -6; b = -18; c = +10;
Δ = b2-4ac
Δ = -182-4·(-6)·10
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{141}}{2*-6}=\frac{18-2\sqrt{141}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{141}}{2*-6}=\frac{18+2\sqrt{141}}{-12}
$