3x(-22+5x)=4

Solution for 3x(-22+5x)=4 equation:

3x(-22+5x)=4

We move all terms to the left:

3x(-22+5x)-(4)=0

We add all the numbers together, and all the variables

3x(5x-22)-4=0

We multiply parentheses

15x^2-66x-4=0

a = 15; b = -66; c = -4;
Δ = b2-4ac
Δ = -662-4·15·(-4)
Δ = 4596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4596}=\sqrt{4*1149}=\sqrt{4}*\sqrt{1149}=2\sqrt{1149}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-2\sqrt{1149}}{2*15}=\frac{66-2\sqrt{1149}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+2\sqrt{1149}}{2*15}=\frac{66+2\sqrt{1149}}{30}
$